-(2x^2-5x+5)=

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Solution for -(2x^2-5x+5)= equation:


Simplifying
-1(2x2 + -5x + 5) = 0

Reorder the terms:
-1(5 + -5x + 2x2) = 0
(5 * -1 + -5x * -1 + 2x2 * -1) = 0
(-5 + 5x + -2x2) = 0

Solving
-5 + 5x + -2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
-2 the coefficient of the squared term: 

Divide each side by '-2'.
2.5 + -2.5x + x2 = 0

Move the constant term to the right:

Add '-2.5' to each side of the equation.
2.5 + -2.5x + -2.5 + x2 = 0 + -2.5

Reorder the terms:
2.5 + -2.5 + -2.5x + x2 = 0 + -2.5

Combine like terms: 2.5 + -2.5 = 0.0
0.0 + -2.5x + x2 = 0 + -2.5
-2.5x + x2 = 0 + -2.5

Combine like terms: 0 + -2.5 = -2.5
-2.5x + x2 = -2.5

The x term is -2.5x.  Take half its coefficient (-1.25).
Square it (1.5625) and add it to both sides.

Add '1.5625' to each side of the equation.
-2.5x + 1.5625 + x2 = -2.5 + 1.5625

Reorder the terms:
1.5625 + -2.5x + x2 = -2.5 + 1.5625

Combine like terms: -2.5 + 1.5625 = -0.9375
1.5625 + -2.5x + x2 = -0.9375

Factor a perfect square on the left side:
(x + -1.25)(x + -1.25) = -0.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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